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what equation describes a line passing through (-6,-5) that is perpendicular to a line described by y=-2/3x?

1 Answer

3 votes

Answer:

The equation of this line would be y = 3/2x + 4

Explanation:

In order to find this equation we must first find the slope of the original line. The original slope (the coefficient of x) is -2/3, which means the new slope will also be 3/2 because perpendicular lines have opposite and reciprocal slopes. Now, we can use this slope along with the point in point-slope form to find the equation of the line.

y - y1 = m(x - x1)

y + 5 = 3/2(x + 6)

y + 5 = 3/2x + 9

y = 3/2x + 4

User Bryan Potts
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