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A parabola has x-int of (-8,0) and (4,0) and a minimum value of -9 in intercept form

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Answer:

The function is 1/4x^2 + x - 8

Explanation:

In Factor form the function is

a(x + 8)(x - 4) where a is a constant to be found.

= a( x^2 + 4x - 32) Note the coefficient of x is positive because the function has a minimum value.

The line of symmetry is x = (-8+4)/2 = -2.

So the minimum value will be the value of f(x) when x = -2, so we have the equation

a(-2+8)(-2-4) = -9

-36a = -9

a = 1/4.



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