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What force is needed to keeps 20kg box moving at a constant velocity when the mk is 0.3021 and the force is applied level to the ground

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Answer:

59.2 N

Step-by-step explanation:

According to Newton's second law, the resultant of the forces acting on the box must be equal to the product between the box's mass and its acceleration:


F_(net)=ma

However, the box is moving at constant velocity, so its acceleration is zero:

a = 0

Therefore, the net force along the direction of motion (parallel to the surface) must be zero.

We have two forces acting along the direction parallel to the ground:

- The applied force, F

- The frictional force,
\mu mg, in the opposite direction, with
\mu = 0.3021 being the coefficient of friction, m = 20 kg the mass of the box and g = 9.8 m/s^2

Therefore, the equation of motion becomes:


F-\mu mg=0

And solving for F, we find:


F=\mu mg=(0.3021)(20 kg)(9.8 m/s^2)=59.2 N

User MarkWalczak
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