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The height, h(t), in feet of an object thrown into the air with an initial upward velocity of 63 feet per second is given by the formula h(t) = -16t2 + 63t, where t is the time in seconds. What is the height, in feet, of the object after 3 seconds?

User ADD
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4 votes

Answer:

The height of the object after 3 seconds is 45 feets.

Explanation:

The height of an object thrown into the air with an initial upward velocity of 63 feet per second is given as


h(t)=-16t^2+63t

Where, h(t) is height of the object in feet and t is the time in seconds.

We have to find the height of the object after 3 seconds. So, substitute t=3.


h(3)=-16(3)^2+63(3)


h(3)=-16(9)+189


h(3)=-144+189


h(3)=45

Therefore height of the object after 3 seconds is 45 feets.

User Peoplespete
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