Question

Please help me. Explanation needed in algebraic form:

A painting, square in shape, is placed in a wooden frame with width of 10% of the length of the side of the painting. The painting was enlarged by 10%. By what percent is the new frame bigger than the original frame if the width of the frame remains the same?

Answer 1

9.09091%

Explanation:

Answer 2

the new frame is bigger than the original frame by 10%

Explanation:

Let the length of the original frame be l,

then it's width is (10% of l)=
`(10)/(100)`×l

=
`(l)/(10)`

hence area of original frame=A=length×width

=
`(l^(2) )/(10)`

now the length of frame is enlarged by 10%

new lenght of frame=l+10%×l

=l+
`(10)/(100)`×l

=
`(11)/(10)`×l

width of new frame==
`(l)/(10)`

area of new frame=length×width

=
`(11l^(2) )/(100)`

percent change=((area of new frame-area of old frame)×100)÷area of old frame

=10%