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Please help me on this

Please help me on this-example-1

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Dad: TtBb

Mom: ttbb

You have to use distribution for dihybrid crosses. Meaning, the first allele of each trait has a equal chance of being paired with the other allele of the other trait. So for example with Dad, I will number the traits:

T(1)t(2)B(3)b(4)

To set up the possibilities from Dad, it would be 13, 14, 23, 24: TB, Tb, tB, tb. Same idea goes for Mom, except since all alleles are the same, you only need to make one column for Mom, since if you did all 4, the other 3 would just be repeats of the 1.

Cross:

tb

TB TtBb

Tb Ttbb

tB ttBb

tb ttbb

The phenotypic ratio is 1 Tall Brown: 1 Tall Blue: 1 Short Brown: 1 Short Blue

User Filnik
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