Question

Please answer formula is in text

Answer 1

For 1 mole of He, there are 6.022*10E23 of He atoms. 2.7 moles of He have:

2.7*6.022*10E23 = 1.626*10E24 atoms

For each He atom formed from fusion reaction of four H atoms, the mass loss is given as 4.59*10E-29kg

The total mass loss for 2.7 moles of He = 1.626*10E24 * 4.59*10E-29

= 7.46*10E-5kg

Energy released in a reaction with mass change is given as 9*10E16J per kg mass

So the total energy released from fusion reaction that has created 2.7 moles of He = 7.46*10E-5 * 9*10E16

= 6.714*10E12 Joules

Answer 2

E=mc^2 n its given 1kg = 9x10^16J

so need to figure out the total mass loss n u can find the energy released

mass loss when 4x H atom combines to form 1x He atom in a fusion reaction is given as 4.59x10^-29kg

1 mole of He has 6.02x10^23 He atoms

so 2.7 moles of He has 2.7x6.02x10^23 He atoms

the total mass loss for 2.7 moles of He created in a fusion reaction

= 2.7x6.02x10^23 x 4.59x10^-29kg

= 7.46x10^-5kg

radiation energy released from this fusion reaction

= 7.46x10^-5 x 9x10^16J

= 6.7x10^12J

its 60 BILLION times more than burning carbon!!