46.5k views
5 votes
Carol has a small Copley of a painting. The dimensions of her copy are shown at the right. The scale of the copy is 0.5 inches: 12 centimeter.

Question A) Find the dimensions of the original painting.

Question B) Find the area of the original painting.

Question C) One centimeter is equal to approximately 0.033 foot. Find the dimensions of the original painting in feet. Round to the nearest thousandth.

Carol has a small Copley of a painting. The dimensions of her copy are shown at the-example-1

2 Answers

2 votes

Answer:

(A) 42 cm by 126 cm.

(B) 5,292 square centimeters.

(C) 1.386 feet by 4.158 feet

Explanation:

The scale of the copy is 0.5 : 12, which means 0.5 inches of the copy represents 12 centimeters actual.

From the given scale we can deduct that 1 inch equals 24 centimeters.

So, the dimensions of the original are


1.75 * 24 =42


5.25 * 24= 126

Therefore, the original painting has dimensions 42 cm by 126 cm. (A)

Notice that the original painting is also rectangular, so its area is


A_(original)=42 * 126 = 5,292 cm^(2) (B)

Now, if 1 centimeter is equivalen to 0.033 foot, the dimensions of the original painting in feet are


42 * 0.033 =1.386 ft\\126 * 0.033=4.158 ft

Therefore, the dimensions in feet are 1.386 feet by 4.158. (C)

User Klew
by
6.2k points
4 votes

Answer:

Question A: The dimensions of the original painting are 42 cm by 126 cm.

Question B: The area of the original painting is
5292cm^2

Question C: The dimensions of the painting in feet are 1.386 ft by 4.158 ft.

Explanation:

Question A:

The scale of the copy is

0.5 inches:12 centimeter.

This means that 1 inch on the scale is 24 centimeters.

Therefore the width of the original painting is:


1.75*24cm=42cm

and the height of is:


5.25*24cm=126cm

Therefore the dimension of the original painting are 42 cm by 126 cm.

Question B;

The area of the original painting is just width multiplied by height:


Area=42cm*126cm=5292cm^2

Question C:

We convert the dimensions of the painting from centimeters to feet:


width=42cm*0.033(feet)/(cm) =1.386\:feet.


height=126cm*0.033(feet)/(cm) =4.158\:feet.

Therefore the dimensions of the original painting in feet are 1.386 ft by 4.158 ft.

User Diana
by
5.4k points