Answer:
y-determinant = 2
Explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/nsqra0idf2ljjp50iean918eophfc2g0io.png)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://img.qammunity.org/2019/formulas/mathematics/middle-school/px0cz8tbxw6vdcb0r3rb1nar7d1gba0qvz.png)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2