Answer:
1. p = 2, q = 10
2. a = 4, b = 3
Explanation:
1. $ pillows and 5 quilts cost £58.
4p + 5q = £58
6 pillows and 5 quilts cost £62.
6p + 5q = £62
So that,
4p + 5q = 58 .............. 1
6p + 5q = 62 ............. 2
Subtract equation 1 from 2
6p - 4p + 5q - 5q = 62 - 58
2p = 4
p =

p = 2
substitute the value of p in equation 1
4(2) + 5q = 58
8 + 5q = 58
5q = 50
q =

q = 10
Thus,
p = 2, q = 10
2. 7 apple pies and 2 banoffee cost £34
7a + 2b = £34
7 apple pies and 5 banoffee cost £43
7a + 5b = £43
So that,
7a + 2b = 34 ............. 1
7a + 5b = 43 ........... 2
Subtract equation 2 from 1
7a - 7a + 5b - 2b = 43 - 34
3b = 9
b =

b = 3
substitute the value of b in equation 1
7a + 2(3) = 34
7a + 6 = 34
7a = 28
a =

a = 4
Thus,
a = 4, b = 3