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Can you please solve this question with procedure, please???? . h (x) = 6x^2+ 3x + 1
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3 votes
Can you please solve this question with procedure, please????

. h (x) = 6x^2+ 3x + 1

User Basanth
by
6.4k points

1 Answer

7 votes

Answer:


Explanation:

H


6x^2+3x+1=0\\a=6,b=3,c=1\\(-b+-√(b^2-4ac) )/2a\\\\(-3+-√(-15) )/(12) \\\\


The roots are:


(-3+-i√(15) )/(12)

User Tim Cooley
by
5.1k points
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