Question

I’ve been stuck on this for way too long. Help please (:

Answer 1

Part 1 : conversion factor required for 30%(m/m) NaCl solution.

30%(m/m) NaCl solution that means 30 grams of NaCl is present in 100 gram of solution.

Conversion factor :
`30\%\text{ of NaCl solution}=\frac{30\text{ g of NaCl}}{100\text{ g of solution}}`

Part 2 : conversion factor required for 8%(v/v) ethanol solution.

8%(v/v) ethanol solution that means 8 ml of ethanol is present in 100 ml of solution.

Conversion factor :
`8\%\text{ of ethanol solution}=\frac{8\text{ ml of ethanol}}{100\text{ ml of solution}}`

Part 3 : conversion factor required for 14%(m/v) fructose solution.

14%(m/v) fructose solution that means 14 grams of fructose is present in 100 ml of solution.

Conversion factor :
`14\%\text{ of fructose solution}=\frac{14\text{ g of fructose}}{100\text{ ml of solution}}`

Part 4 : conversion factor required for 5.0 M HBr solution.

'M' represent the 'molarity' which is defined as the number of moles of solute present in one liter of solution.

5.0 M HBr solution that means 5 moles of HBr is present in 1 liter of solution.

Conversion factor :
`5.0M\text{ HBr solution}=\frac{5\text{ moles of HBr}}{1\text{ L of solution}}`