Answer:
C. 3.8 years
Explanation:
Exponential Growth
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
The actual population of deer in a forest is Po=800 individuals. It's been predicted the population will grow at a rate of 20% per year (r=0.2).
We have enough information to write the exponential model:


It's required to find the number of years required for the population of deers to double, that is, P = 2*Po = 1600. We need to solve for t:

Dividing by 800:

Taking logarithms:

Dividing by log 1.2:

Calculating:
t = 3.8 years
Answer: C. 3.8 years