Question

The dimensions of a brick that weighs 25 N are 0.19 m × 0.07 m × 0.095 m. What pressure does the brick exert on the ground if it is resting on its largest face? 1385 N/m2 19,786 N/m2 3759 N/m2 1900 N/m2

Answer 1

1385 N/m^2

Step-by-step explanation:

The pressure exerted by the brick on the ground is given by:

`p=(F)/(A)`

where F is the weight of the brick and A is the area of its largest face.

The area of the largest face is given by the two largest sides of the brick, therefore:

`A=(0.19 m)(0.095 m)=0.01805 m^2`

The force exerted by the brick is the weight:

`F=25 N`

So, the pressure is

`p=(25 N)/(0.01805 m^2)=1385 N/m^2`