Explanation:
![4csc(2x) = 2csc^2(x) tan(x)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ux38p0naougpy7i7sxwoh8yqa3g6unermj.png)
We start with Left hand side
We know that csc(x) = 1/ sin(x)
So csc(2x) is replaced by 1/sin(2x)
![4 (1)/(sin(2x))](https://img.qammunity.org/2019/formulas/mathematics/high-school/rsg12tw79f0l3zdkkci5e8zr6hgxuuv0rg.png)
Also we use identity
sin(2x) = 2 sin(x) cos(x)
![4 (1)/(2sin(x)cos(x))](https://img.qammunity.org/2019/formulas/mathematics/high-school/f52l0ay0mipju9zx5crwvs0vxsplswf99j.png)
4 divide by 2 is 2
Now we multiply top and bottom by sin(x) because we need tan(x) in our answer
![2(1*sin(x))/(sin(x)cos(x)*sin(x))](https://img.qammunity.org/2019/formulas/mathematics/high-school/pl8jytdlc4wcaxbopostl5ro6v3u5mpiq2.png)
![2(sin(x))/(sin^2(x)cos(x))](https://img.qammunity.org/2019/formulas/mathematics/high-school/afymnfznqrgcdcflhmb19pj0w32l1mef3i.png)
![2(1)/(sin^2(x)) (sin(x))/(cos(x))](https://img.qammunity.org/2019/formulas/mathematics/high-school/28dcsu32fltstyq11adxc234bijtob2euz.png)
We know that sinx/ cosx = tan(x)
Also 1/ sin(x)= csc(x)
so it becomes 2csc^2(x) tan(x) , Right hand side
Hence verified