Answer:
78 persons
Explanation:
Given
![Budget = 3000](https://img.qammunity.org/2022/formulas/mathematics/college/uq7hlcgvowlfsg4pvlkr0muczef0use8yk.png)
![Clean\ up = 100](https://img.qammunity.org/2022/formulas/mathematics/college/8jw72fkjfnm7u4yx66i4r9j9iz50e9b4gk.png)
![Rate = 37\ per\ person](https://img.qammunity.org/2022/formulas/mathematics/college/frq3evst2ompt7md751junwrle2vafmq49.png)
Required
Determine the maximum number of person that can be invited
Let the number of persons be p.
If the hall charges $37 for 1 person, then it will charge $37p for p persons.
So:
![Charges = 37p](https://img.qammunity.org/2022/formulas/mathematics/college/zgh7zi76369m5b2psmfqzqz1g4lgp0z492.png)
The expression becomes:
![Clean\ up + Charges = Budget](https://img.qammunity.org/2022/formulas/mathematics/college/2vwzrm09b5z2vb0loqumhu858mug79u46j.png)
Substitute values for Clean up, Charges and Budget
![100 + 37p = 3000](https://img.qammunity.org/2022/formulas/mathematics/college/9u41r4h9ojluh0r18k2jcfhzgiuy6lnued.png)
Subtract 100 from both sides
![100 - 100 + 37p = 3000 - 100](https://img.qammunity.org/2022/formulas/mathematics/college/37k5h4zs7gkaq4jczmct5c4r9xea8me87s.png)
![37p = 3000 - 100](https://img.qammunity.org/2022/formulas/mathematics/college/4wejtunug4fm25eh5a52kgq9urev1ngide.png)
![37p = 2900](https://img.qammunity.org/2022/formulas/mathematics/college/o1bs7y6tkekpuf26r4uwqbn9iqqfismr2m.png)
Make p the subject
![p = (2900)/(37)](https://img.qammunity.org/2022/formulas/mathematics/college/snx0jdmeoahnzxr84gp21urfqsk2pgk4ui.png)
![p = 78.378](https://img.qammunity.org/2022/formulas/mathematics/college/7jihyoon208g4nrg0oxc6dwjeiw6nr7hcx.png)
Round down
![p = 78](https://img.qammunity.org/2022/formulas/mathematics/college/tkrgk5v8gt2de92sidi4tzcewt2prou4bw.png)
Hence, they can only invite 78 people to stay within budget