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For questions 8 – 10, answer the questions about tangent-tangent angles.

For questions 8 – 10, answer the questions about tangent-tangent angles.-example-1

1 Answer

9 votes

Answer:

m(arc ZWY) = 305°

Explanation:

8). Formula for the angle formed outside the circle by the intersection of two tangents or two secants is,

Angle formed by two tangents =
(1)/(2)(\text{Difference of intercepted arcs})

=
(1)/(2)(220-140)

=
(1)/(2)(80)

= 40°

9). Following the same rule as above,

Angle formed between two tangents =
(1)/(2)(\text{Difference of intercepted arcs})

125 =
(1)/(2)[m(\text{major arc})-m(\text{minor arc})]

250 =
[m(\text{arc ZWY})-m(\text{arc ZY})]

250 = m(arc ZWY) - 55

m(arc ZWY) = 305°

Therefore, measure of arc ZWY = 305° will be the answer.

10). m(arc BAC) =
(1)/(2)([m(\text{arc BDC})-m(\text{arc BC})])

=
(1)/(2)(254-106)

=
(148)/(2)

= 74°