Answer:
Point-Slope form: The equation of line is given by:
......[1]
where m is the slope and
is the point on the line.
From the given graph:
Consider two points i.e,
and (-0.5, 0)
Calculate slope:
Formula for slope is given by;
![\text{Slope}(m) = (y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/q8o8ts33s2gxo0wjmxk60z2k4u08cw7yy0.png)
Substitute the given values we have;
![m = (0-1)/(-0.5-0) = (-1)/(-0.5) = (10)/(5) =2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6zdwzeznyjn8fhyzyweih89egsrm73gw1s.png)
Now, substitute the value of m = 2 and (0, 1) in equation [1] we have;
![y-1 = 2(x-0)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/bowtt46usx4l7zls777t6tfyyesfs4xp4n.png)
y-1 = 2x
Add 1 to both sides we get;
y = 2x+1
On comparing equation y = 2x+1 with the slope intercept form of a line (i.e, y = mx+b) then we have;
slope(m) = 2
y-intercept(b) = 1
therefore, the slope of the function:
m = 2
y-intercept(b) = 1
and the equation represents the graph: y = 2x+1