Question

When 200.0mL of water is heated from 15.0 deg Celsius to 40.0 deg Celsius, how much thermal energy is absorbed by the water?

Answer 1

Heat required to raise the temperature of water is given as

`Q = ms\Delta T`

here we know that

`m = mass = 200 mL = 0.200 kg`

initial temperature = 15 degree C

final temperature = 40 degree C

specific heat capacity = 4186 J/kg C

now by the above formula we will have

`Q = 0.200 (4186) (40 - 15) = 20930 J`