Question

The equation of a circle is given below ( x-20)^2 + (y-0.05)^2 =81 what is its center? What is its radius?

Answer 1

see explanation

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 20)² + (y - 0.05)² = 81 is in this form

with centre = (20, 0.05) and r =
`√(81)` = 9

Answer 2

So the center is at (20,.05) and the radius is 9

Explanation:

The equation of a circle can be written in the form

(x-h) ^2 + (y-k) ^2 = r^2

where (h,k) is the center and r is the radius

Lets write our equation in that form

( x-20)^2 + (y-0.05)^2 =81

( x-20)^2 + (y-0.05)^2 =9^2

So the center is at (20,.05) and the radius is 9