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Match the addition and subtraction problems to their solutions:

Match the addition and subtraction problems to their solutions:-example-1
User Yakunins
by
8.0k points

2 Answers

10 votes

Answer:

1. B

2.c

3. E

4.d

5.A

Explanation:

User Deept Raghav
by
8.3k points
5 votes

Answer:

we conclude that:

5/7 - 3/7: B 2/7

1/6+3/6: C 2/3

1/2+1/4: E 3/4

1/5+1/2: D 7/10

1/6-1/8: A 1/24

Explanation:

1)

Given the expression


(5)/(7)-(3)/(7)

Apply the fraction rule:
(a)/(c)-(b)/(c)=(a-b)/(c)


(5)/(7)-(3)/(7)=(5-3)/(7)

Add the numbers:
5-3=2


=(2)/(7)

2)

Given the expression


(1)/(6)+(3)/(6)

Apply the fraction rule:
(a)/(c)+(b)/(c)=(a+b)/(c)


(1)/(6)+(3)/(6)=(1+3)/(6)

Add the numbers:
1+3=4


=(4)/(6)

Cancel 4/6: 2/3


=(2)/(3)

3)

Given the expression


(1)/(2)+(1)/(4)

Lease common multiplier of 2, 4: 4

Adjust fractions based on LCM


(1)/(2)+(1)/(4)=(2)/(4)+(1)/(4)

Apply the fraction rule:
(a)/(c)+(b)/(c)=(a+b)/(c)


(2)/(4)+(1)/(4)=(2+1)/(4)

Add the numbers:
2+1=3


=(3)/(4)

4)


(1)/(5)+(1)/(2)

Lease common multiplier of 5, 2: 10

Adjust fractions based on LCM


(1)/(5)+(1)/(2)=(2)/(10)+(5)/(10)

Apply the fraction rule:
(a)/(c)+(b)/(c)=(a+b)/(c)


(2)/(10)+(5)/(10)=(2+5)/(10)

Add the numbers: 2+5 = 7


=(7)/(10)

5)

Given the expression


(1)/(6)-(1)/(8)

Lease common multiplier of 6, 8: 24

Adjust fractions based on LCM


(1)/(6)-(1)/(8)=(4)/(24)-(3)/(24)

Apply the fraction rule:
(a)/(c)-(b)/(c)=(a-b)/(c)


(4)/(24)-(3)/(24)=(4-3)/(24)


=(1)/(24)

Therefore, we conclude that:

5/7 - 3/7: B 2/7

1/6+3/6: C 2/3

1/2+1/4: E 3/4

1/5+1/2: D 7/10

1/6-1/8: A 1/24

User Pkpk
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