Question

What is the specific heat of an unknown substance if a 14 g sample releases 60 calories as its temperature changes from 40°C to 10°C? SHOW YOUR WORK​

Answer 1

Cp = 0.142 [cal/g*°C].

Step-by-step explanation:

In order to solve this problem, we must use the following equation of thermal energy.

`Q=m*c_(p)*(T_(initial)-T_(final))`

where:

Q = heat energy = 60 [cal]

Cp = specific heat [cal/g*°C]

T_final = final temperature = 10[°C]

T_initial = initial temperature =40[°C]

m = mass of the substance = 14 [g]

Now replacing:

`60=14*C_(p)*(40-10)\\C_(p)=0.142[(cal)/(g*C) ]`