Question

write a point-slope equation for the line that passes through the point (1,6) and is parallel to the line given by y=5x+25 do not use parenthesis on the y side

Answer 1

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (relevant later)

Point-slope form:

y - y₁ = m(x - x₁) "m" is the slope

For lines to be parallel, their slopes have to be the SAME

The given line's slope is 5, so the parallel line's slope is also 5.

So you know:

m = 5

(x₁ , y₁) = (1 , 6)

Now you can plug this in:

y - y₁ = m(x - x₁)

y - 6 = 5(x - 1)

Answer 2

`y-6=5(x-1)`

Explanation:

To make the line parallel, it has to have the same slope as the other. Because it is in slope-intercept form, we can see that the slope of the line is 5.

Now we have all of the numbers we need for point-slope form. The point-slope form looks like this:

`y-y_(1)=m(x-x_(1))`

So when we input our values for the variables, the equation is:

`y-6=5(x-1)`