Question

A fighter jet accelerates from 10 m/s to 75 m/s in 7.0 s. The acceleration of the jet is

Answer 1

The acceleration of the fighter jet is calculated by taking the change in velocity (75 m/s - 10 m/s) divided by the time (7.0 s), which equals 9.29 m/s².

Step-by-step explanation:

The acceleration of a fighter jet can be calculated using the formula a = Δv/Δt, where a is acceleration, Δv is the change in velocity, and Δt is the change in time. The jet accelerates from an initial velocity (vi) of 10 m/s to a final velocity (vf) of 75 m/s in a time interval (Δt) of 7.0 s. Therefore, the acceleration can be calculated as follows:

a = (vf - vi) / Δt = (75 m/s - 10 m/s) / 7.0 s = 65 m/s / 7.0 s = 9.29 m/s2

So, the acceleration of the jet is 9.29 m/s2.

Answer 2

acceleration = final velocity - inital / time
a = 75-10 / 7
a = 65 / 7
a = 9.29 m/s^2