Question

How much heat is absorbed by 17 grams of water that is heated from 50°C to 120°C? (Specific heat capacity of water is 1.0 cal/gºC) SHOW YOUR WORK *​

Answer 1

Q = 1190 [cal]

Step-by-step explanation:

In order to solve this problem, we must use the following equation of thermal energy.

`Q=m*C_(p)*(T_(final)-T_(initial))`

where:

Q = heat energy [cal]

Cp = specific heat = 1 [cal/g*°C]

T_final = final temperature = 120 [°C]

T_initial = initial temperature = 50 [°C]

m = mass of the substance = 17 [g]

Now replacing:

`Q=17*1*(120-50)\\Q=1190[cal]`