Write the equation of the line containing the point (3, –2) and having a slope of 2 in slope-intercept form.

Question

asked Oct 5, 2019 220k views

2 Answers

AlwaysVBNET · Answer 1 · 2019-10-08T12:24:51+0000

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept

We have the slope m = 2 and the point (3, -2) → x = 3 and y = -2.

Substitute:

-2=(2)(3)+b

-2=6+b subtract 6 from both sides

$-8=b\to b=-8$

Substitute to the equation y = mx + b:

Metdos · Answer 2 · 2019-10-11T19:59:51+0000

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0 or (0,y))

You know m = 2, so you can plug it into the equation

y = 2x + b

To find "b", plug in the point (3, -2) into the equation

y = 2x + b

-2 = 2(3) + b

-2 = 6 + b

-8 = b

y = 2x - 8