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Help me understand this problem-example-1

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It ΔABC and ΔXYZ are similar, then the sides of the triangles are in proportion.


(AB)/(XY)=(BC)/(YZ)=(AC)/(XZ)

We have BC = 8, AC = 7, Y = 28, XZ = 49 and YZ = 56. Substitute:


(AB)/(XY)=(BC)/(YZ)\to(AB)/(28)=(8)/(56)\qquad\text{cross multiply}\\\\56AB=(8)(28)\qquad\text{divide both sides by 56}\\\\AB=(224)/(56)\\\\\boxed{AB=4}

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