Answer:
![y=(3)/(2) x+6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/6dpir5h2u442drvyatjtog6s6qur0qkjm6.png)
Explanation:
We are given the following equation and we are supposed to solve y in terms of x. It simpler terms, it means that we have to make y the subject of the equation while x being used in it as it is:
![(2)/(3) y-4=x](https://img.qammunity.org/2019/formulas/mathematics/middle-school/v5fz7uhbmis3bl5h6eptyqkavz103imdr4.png)
Taking the constant 4 to the side where x is to get:
![(2)/(3) y=x+4](https://img.qammunity.org/2019/formulas/mathematics/middle-school/kv8x8kmq59ylbybrx3oprscusi6o470vul.png)
Multiplying the denominator 3 to the other side of the equation to get:
![2y=3x+12](https://img.qammunity.org/2019/formulas/mathematics/middle-school/apji3jnfyw3xzd52wmcb2xsbm9zcrhpjey.png)
Isolating y to make it the subject:
![y=(3)/(2) x+(12)/(2)\\ \\y=(3)/(2) x+6](https://img.qammunity.org/2019/formulas/mathematics/middle-school/p5yq2rcboula12inl7owll54ge9ijgsslh.png)