Question

30°-60°-90° special triangle. how do I solve?

Answer 1

In the trinagle 30 - 60 - 90 the sides are in proportion 1 : √3 : 2.

Look at the picture.

We have:

`a=2\sqrt5`

Therefore

`A=2a\to A=(2)(2\sqrt5)=4\sqrt5\\\\B=a\sqrt3\to B=(2\sqrt5)(\sqrt3)=2√((5)(3))=2√(15)`

Answer: A = 4√5, B = 2√15