Question

Please help me on what the next 3 terms would be

Answer 1

`z_0=3-2i\\\\z_(n+1)=2z_n+i\\\\z_1=z_(0+1)=2z_0+i\to z_1=2(3-2i)+i=6-4i+i=6-3i\\\\z_2=z_(1+1)=2z_1+i\to z_2=2(6-3i)+i=12-6i+i=12-5i\\\\z_3=z_2+1}=2z_2+i\to z_3=2(12-5i)+i=24-10i+i=24-9i\\\\Answer:\ \boxed{6-3i;\ 12-5i;\ 24-9i}`