2 Answers

Stefan Scherer · Answer 1 · 2019-02-13T16:25:54+0000

Answer:

C. b^27

Explanation:

By the definition of exponents

(b^9)^3=b^9*b^9*b^9

And since for any real numbers
r,x, and

r^x*r^y=r^((x+y))

This makes

$(b^9)^3=b^9*b^9*b^9=b^{{9+9+9}}=\boxed{b^(27)}$

Which is choice C.

Alternatively, we could use the identity

(r^x)^y=r^(xy)

in which case

$(b^9)^3=b^((9*3))= \boxed{b^(27)}$

which is the same answer.

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