Question

Assuming no friction form air, how far will a dropped rock fall in 10 seconds

Answer 1

Given that

time (t) = 10 s ,

(S) = ?

We know that S = ut+ 1/2 a.t² m

since free fall and no air friction,

a = g = 9.81 m/s² ; initial velocity u= 0

S = 0 + [1/2 × 9.81 ×10²]

S = 490.5 m