Answer:
Given equation:
![Px+5 = -4x+ Q](https://img.qammunity.org/2019/formulas/mathematics/middle-school/t6a1qxgn257pb3e0g8i5xfu9163ujdvm69.png)
Add 4x on both sides we get;
Px + 5 + 4x = -4x + Qc+ 4x
Simplify:
Px +4x + 5 = Q
or
x(P+4) = Q - 5
Divide P+4 on both sides we get;
![x = (Q-5)/(P+4)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/c6xrkq3gxvrsp4x25bpn1lfgdth0421h40.png)
If we set Q-5 = 0 and P +4 = 0, there will be no solutions.
Since, No solution would mean that there is no answer to the equation.
⇒
![Q -5 = 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9av3jq70rlf8sev9pxoh3gke62i2t3sb2t.png)
or
Q = 5
and
⇒
![P +4 = 0](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9dmavfn47on4ch9l3nwwojn6oduzqz30ou.png)
or
P= -4
Therefore, the values of P = -4 and Q = 5 results in an equation with no solutions.