Question

If a rock is dropped with a weight of 50kg and friction due to air resistance produces a force of 98N, what is the net force in the Y direction?

PLEASE HELP 11 POINTS

Answer 1

The net force is 392N, pointing down.

Step-by-step explanation:

The net force is the sum of all forces acting on the rock, namely the gravity ("+" acting downward) and the friction force due to air resistance ("-" acting upward):

`F_(net) = F_g - F_(air)\\F_(net) = m\cdot g - F_(air) = 50kg\cdot 9.8(m)/(s^2)-98N= (490-98)N=392N`

The net force is 392N and pointing down (positive)/