Answer:
D) (1,5)
Explanation:
You have to substitute so...
(-1,0):
y = 3x + 2
0 = 3(-1) + 2
0 = -3 +2
0 = -1
(-1,0) is NOT a solution.
(0,3):
y= 3x + 2
3 = 3(0) + 2
3 = 0 +2
3 = 2
(0,3) is NOT a solution.
(1/3,1):
y = 3x + 2
1 = 3(1/3) + 2
1 = 1 + 2
1 = 3
(1/3,1) is NOT a solution.
(1,5):
y = 3x + 2
5 = 3(1) + 2
5 = 3 + 2
5 = 5
(1,5) IS a solution.