Answer:
{x = 1 , y = 3
Explanation:
Solve the following system: using elimination:
{2 x + 5 y = 17 | (equation 1)
{6 x - 5 y = -9 | (equation 2)
Swap equation 1 with equation 2:
{6 x - 5 y = -9 | (equation 1)
{2 x + 5 y = 17 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{6 x - 5 y = -9 | (equation 1)
{0 x+(20 y)/3 = 20 | (equation 2)
Multiply equation 2 by 3/20:
{6 x - 5 y = -9 | (equation 1)
{0 x+y = 3 | (equation 2)
Add 5 × (equation 2) to equation 1:
{6 x+0 y = 6 | (equation 1)
{0 x+y = 3 | (equation 2)
Divide equation 1 by 6:
{x+0 y = 1 | (equation 1)
{0 x+y = 3 | (equation 2)
Collect results:
Answer: {x = 1 , y = 3