Answer: The traveler's speed off the walkway= 3 ft/s
The speed of the moving walkway= 2 ft/s
Explanation:
Given: A traveler is walking on a moving walkway in an airport.
Let 't' be the traveler's speed off the walkway and 'w' be the speed of walkway.
Then the traveler's ground speed against the walkway (t-w)= 1 ft/s
And the traveler's ground speed with the walkway (t+w)= 5 ft/s
thus we get the following equations

Adding (1) and (2), we get

Subtract (2) from (1), we get

Therefore, the traveler's speed off the walkway= 3 ft/s
The speed of the moving walkway= 2 ft/s