Question

HELPPP PLEASEEE!!! Find the perimeter of ΔTAP with vertices T(1, 4), A(4,4), and P(3,0) to the nearest tenth unit.

Answer 1

Answer: 11.6 units.

Explanation:

1. Plot the points as you can see in the graph attached.

2. As you can see, the lenght TA is 3 units.

3. Apply the formula for calculate the distance between two points, to calculate the length TP and TA. The formula is:

`d=\sqrt{(x_2-x_1)^(2)+(y_2-y_1)^(2)}`

4. Therefore, you have:

`TP=\sqrt{(1-3)^(2)+(4-0)^(2)}=4.47units`

`AP=\sqrt{(4-3)^(2)+(4-0)^(2)}=4.12units`

5. The perimeter is the sum of the the lenght of each side, therefore:

`Perimeter=3units+4.47units+4.12units\\Perimeter=11.59units`

6. To the nearest tenth unit:

`Perimeter=11.6units`