Question

What is the best approximation of the length of segment QS? (Note: cos 80° = 0.17)

(Round your answer to the nearest tenth.)

Answer 1

Answer:
`QS=11.8cm`

Explanation:

1. You have the following information:

- The lenght of
`RS` is 2 centimeters.

- The angle m∠S=80°.

- Cos80°=0.17

2. Therefore, you can calculate the lenght of the segment
`QS` as following:

`cos80=(adjacent)/(hypotenuse)`

`adjacent=2cm\\hypotenuse=QS\\cos80=0.17`

3. Substitute values and solve for
`QS`:

`0.17=(2cm)/(QS)\\QS=(2cm)/(0.17) \\QS=11.76cm`

4. To the nearest tenth:

`QS=11.8cm`