Answer:
option B and C
Explanation:
Lets check each function
Lets simplify
![(x^2-25)/(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/wl49sgs0m1uyu24ufkyy90ehnd7h07jzwv.png)
factor the numerator
![x^2-25 = (x+5)(x-5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/1g3nvitkpijvpfwium1xu9eppf8llot5x2.png)
![((x+5)(x-5)/(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/80jk4vsx413udspbai3gk8xm98ltmg28z5.png)
Cancel out x+5 so we are left with x-5
When x=-5 then f(x) = x-5= -5-5 = -10
To make the function continuous at x=-5 the value of f(x) should be -10
So option B is correct
Now we check with option C and D
Lets simplify
![(x^2+10x+25)/(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/p6c1nan8o3g9vvgbd725yt07o5ty2bo3yx.png)
factor the numerator
![x^2+10x+25 = (x+5)(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/khukv0hnmagvqf8chjbyrna08x1qfitjf9.png)
![((x+5)(x-5)/(x+5)](https://img.qammunity.org/2019/formulas/mathematics/high-school/80jk4vsx413udspbai3gk8xm98ltmg28z5.png)
Cancel out x+5 , so we are left with x+5
When x=-5 then f(x) = x+5= -5+5 = 0
To make the function continuous at x=-5 the value of f(x) should be 0
So option C is correct