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The angle of elevation to the top of a skyscraper is measured to be 2 degrees from a point on the ground 1 mile from the building. How tall is the skyscraper?

User Eboubaker
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1 Answer

3 votes

Answer:

0.034921 miles or 1843774 feet tall

Explanation:

Using trigonometric functions we know that
x=rcos(\theta) and
y=rsin(\theta) where
\theta=angle and r is the hypotenuse of the triangle.

First we will calculate the hypotenuse using the x equation, since we know x = 1 mile (distance from the building on the ground) we have:


x=rcos(\theta)\\\\1=rcos(2)\\\\r=(1)/(cos(2)) \approx. 1.0061mi

Now we will calculate the height of the building using the y equation and so:


y=rsin(\theta)\\\\y=(1)/(cos(2)) * sin(2) = (sin(2))/(cos(2))=tan(2)=0.034921mi

The building is 0.034921 miles or approximately 184.3774 feet tall.

User Shankar
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