Question

Please show all the steps and work. The answer is -3.9 m/s2

Answer 1

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

`v^2-u^2=2as\\\\a=(v^2-u^2)/(2s)\\\\a=(0^2-66^2)/(2(560))\\\\a=-3.9\ m/s^2`

Therefore, the acceleration of the airplane is
`-3.9\ m/s^2`