2 Answers

Cosjav · Answer 1 · 2019-06-06T02:38:45+0000

Answer:

D)
$(\sqrt[4]{2x -8} )^4 = (-\sqrt[4]{2x + 8} )^4$

Explanation:

The given equation is
$\sqrt[4]{2x - 8}  + \sqrt[4]{2x + 8 } = 0$

Before, solve this equation, we have to get rid off the radical sign.

So we move the second term on the other side.

$\sqrt[4]{2x-8} = -\sqrt[4]{2x + 8}$

Since we have to radical of 4, we need to raise the power to 4 on both sides

$(\sqrt[4]{2x - 8)} )^4 = (-\sqrt[4]{2x + 8} )^4\\$

Thank you.

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