Question

1. 5h-9+-16+6h

2. 4x+4=9x-36

3.which of the following equation has an infinite number of solutions?
A. 3x-3+-4x B.2y+4-y+16 C. 7x+5=4x+5+3x D.6y-2+2(y=1)

Answer 1

1) 11h - 25

2) 8

3) C

Explanation:

1) 5h-9+-16+6h

+ and - together makes -

5h - 9 - 16 + 6h

Arrange the like terms together

5h + 6h - 9 - 16

= 11h - (9+16)

= 11h - 25

2) 4x+4=9x-36

Subtract 4x from both sides

4x+4-4x = 9x-36-4x

Cancl out 4x and -4x from the left side

4 = 9x - 4x -36

=> 4 = 5x -36

Add 36 to both sides

4+36 = 5x -36 + 36

Cancel out -36 and +36 from the right side

=> 40 = 5x

Flip both the sides of the equation

5x = 40

Dividing both sides by 5

`(5x)/(5) = (40)/(5)`

Cancel out the 5's on the top and bottom of the left side

x = 8

3) 7x+5 = 4x+5+3x

Arrange the like terms together on the right side

7x+5 = 4x+3x+5

=> 7x+5 = 7x+5

Subtract 5 from both sides

7x+5-5 = 7x+5-5

Cancel out +5 and -5 on both the sides

7x = 7x

Divide both sides by 7

`(7x)/(7) = (7x)/(7)`

Cancel out the 7's from the top and bottom of both sides

x = x

which can be true for infinite value of x like 1=1, 2=2, 3=3,.............