Question

Please show the work and steps. The answer is (3.3 s, 15 m/s)

Answer 1

t = 3.3 s and V = 15 m/s

Step-by-step explanation:

Given that,

Distance covered by the car, d = 50 m

Initial speed, u = 5 m/s

Final speed, v = 25 m/s

Firstly we can find the acceleration of the car using third equation of motion. i.e.

`v^2-u^2=2as\\\\a=(v^2-u^2)/(2d)\\\\a=((25)^2-(5)^2)/(2(50))\\\\a=6\ m/s^2`

Let t is the time taken by the car to occur this.

`t=(v-u)/(a)\\\\t=(25-5)/(6)\\\\t=3.3\ s`

Let v is the average velocity of the car. It can be calculated as follows :

`V=(u+v)/(2)\\\\V=(25+5)/(2)\\\\V=(30)/(2)\\\\V=15\ m/s`

So, the time taken by the car to occur this is 3.3 seconds and the average velocity of the car is 15 m/s.