Question

Help me with these math questions....

Answer 1

Answer: cotθ

Step-by-step explanation:

tanθ * cos²θ * csc²θ

=
`(sin\theta)/(cos\theta) * \frac{cos\theta*cos\theta}{} *(1)/(sin\theta*sin\theta)`

=
`(cos\theta)/(sin\theta)`

= cotθ

Answer: B

Step-by-step explanation:

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

• reflection over the x-axis
• vertical shift up 3 units

Answers:

• a. Quadrant II
• b. negative
• c.
  `(\pi)/(6)`
• d. C
• e.
  `-(√(3))/(3)`

Step-by-step explanation:

`(17\pi)/(6) - (12\pi)/(6) = (5\pi)/(6)`

a) Quadrant 2 is:
`(\pi)/(2) < \theta < \pi`

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c)
`\pi-(5\pi)/(6)` =
`(\pi)/(6)`

d) the reference line is above the x-axis so it is negative -->
`-tan(\pi)/(6)`

e)
`tan((5\pi)/(6))=(1)/(-√(3))=-(√(3))/(3)`