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Help me with these math questions.

Help me with these math questions.-example-1
Help me with these math questions.-example-1
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Help me with these math questions.-example-3
User Okdewit
by
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1 Answer

3 votes

graph A

no x-intercept

no y-intercept

H.A is y = 5

V. A. is x = 0

*****************************************

Answer:
(150)/(31)

Step by step explanation:

log₆(5x + 6) - log₆(x - 4) = 2

log₆
((5x+6)/(x-4)) = 2


((5x+6)/(x-4)) = 6²


((5x+6)/(x-4)) = 36

5x + 6 = 36(x - 4)

5x + 6 = 36x - 144

6 = 31x - 144

150 = 31x


(150)/(31) = x

**********************************************************

Answers:

  • a. (-1, -5)
  • b. up
  • c. x = -1
  • d.
    (-2+√(15))/(3) and(-2-√(15))/(3)
  • e. -2
  • f. see attachment
  • g. domain (-∞, ∞) range [-5, ∞)

Step-by-step explanation:

f(x) = 3x² + 6x - 2

a=3 b=6 c=-2

x =
(-b)/(2a) =(-6)/(2(3)) = (-6)/(6) = -1

Axis Of Symmetry: x = -1

f(-1) = 3(-1)² + 6(-1) - 2

= 3 - 6 - 2

= -5

Vertex: (-1, -5)

x =
\frac{-b+/-\sqrt{b^(2)-4ac}}{2a}

=
\frac{-6+/-\sqrt{6^(2)-4(3)(-2)}}{2(3)}

=
(-6+/-√(36+24))/(6)

=
(-6+/-√(60))/(6)

=
(-6+/-2√(15))/(6)

=
(-2+/-√(15))/(3)

x-intercepts:
(-2+/-√(15))/(3)



Help me with these math questions.-example-1
User Jbrtrnd
by
6.5k points