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During the first 5 seconds of a rocket launch, the momentum of the rocket increased by 10,000 kg m/s. What was the impulse applied to the rocket during this time?

User Npjc
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1 Answer

2 votes

Answer:

10,000 kg m/s

Step-by-step explanation:

The impulse exerted on an object is equal to the change in momentum of the object itself:


I=F \Delta t = \Delta p

where

I is the impulse

F is the force applied


\Delta t is the time during which the force has been applied


\Delta p is the change in momentum

In this problem, we are already given the change in momentum of the rocket: since the rocket starts from rest, its change in momentum is equal to its momentum after 5 seconds,


\Delta p = 10,000 kg m/s

and so, the impulse is equal to this value.


User Jilouc
by
8.6k points
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