Question

A 1.0 kg book is at rest on a table top diagram the forces acting on the book

Answer 1

In the diagram attached, we will be able to see that the total force
`F` acting on the book is zero, according to the First Newton law, which states that an object is in equilibrium is the total force exerted on it is zero:

`F=F_(T)-W=0` (1)

Which is the same as:

`F_(T)=W` (2)

Where
`W` is the weight of the book, which is the product of the mass
`m` of the book and the gravity acceleration
`g`:

`W=mg` (3)

Being
`m=1.0kg` and
`9.8(m)/(s^(2))`, the weight of the book is:

`W=(1.0kg)(9.8(m)/(s^(2)))`

`W=9.8N` (4)

Then, equation (2) means that the force
`W` due to the weight acting on the book is the same in magnitude but in opposite direction to the force
`F_(T)` the table exerts on the book, which is in accordance with the third Newton law of action and reaction.