Question

What is the initial value of the function represented by this table? (5 points)

x . y
0 . 5
1 . 9
2 . 13

Answer 1

5 is the initial value

Explanation:

From the table we can see that the values of y are increasing by 4

Lets use two points and find out slope

`slope = (y_2-y_1)/(x_2-x_1)`

we use points (0,5) (1,9)

`slope = (9-5)/(1-0)=4`

slope m= 5

Now we use y=mx+b equation

m= slope and b= y intercept, plug in (0,5) and find out b

y=4x+b

5= 4(0) +b

so b= 5

b=5 is the initial value of the function

Answer 2

5 is the initial value

Explanation:

From the table we can see that the values of y are increasing by 4

Lets use two points and find out slope

formula of slope

slope=m=
`(y2-y1)/(x2-x1)`

putting points (0,5) (1,9) in equation of slope

m=
`(9-5)/(1-0)`

slope m= 4

we know y=mx+b

m= slope and b= y intercept, plug in (0,5) and find out b

b=?

x=0

m=4

y=5

putting these values in y=mx+b

y=4x+b

5= 4(0) +b

so b= 5

b=5 is the initial value of the function